RF coaxial connector If the inner conductor hole of the jack is smaller than the specified size, when the pin of the inner conductor of the pin enters the jack, the jack will be over-expanded, and the shape variable exceeds the elastic deformation range, thereby causing plastic deformation. , thereby affecting the inner conductor of the jack, resulting in damage to the part. On the other hand, if the diameter of the pin is too small, when the pin and the socket are engaged, since the gap between the pin and the wall of the jack is too large, the two inner conductors cannot be in close contact, so that the contact resistance becomes large, and the electrical properties of the connector The indicator will fall. If you want to change this situation, you should consider whether the socket and the pin are properly matched. It can be measured by the insertion force and the holding force when the standard gauge pin and the inner conductor of the jack are matched. For the N-type connector, the insertion force of the diameter Φ1.6760+0.005 standard gauge pin and the socket should be ≤9N, and the retaining force when the diameter Φ1.6000-0.005 standard gauge pin and the inner conductor of the jack are matched ≥0.56N. We can use the insertion force and the holding force as a test standard. By adjusting the size and tolerance of the jack and the pin, and the aging process of the inner conductor of the jack, the insertion force and the holding force between the pin and the jack are at A suitable range.